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Error: __init__() got an unexpected keyword argument 'n_splits'

I am going to perform ShuffleSplit() method for California housing dataset (Source: https://www.dcc.fc.up.pt/~ltorgo/Regression/cal_housing.html) to fit SGD regression.

However, the 'n_splits' error is occurred when method is applied.

The code is following:

ShuffleSplit()

from sklearn import cross_validation, grid_search, linear_model, metrics
import numpy as np
import pandas as pd


from sklearn.preprocessing import scale
from sklearn.cross_validation import ShuffleSplit


housing_data = pd.read_csv('cal_housing.csv', header = 0, sep = ',')
housing_data.fillna(housing_data.mean(), inplace=True)
df=pd.get_dummies(housing_data)


y_target = housing_data['median_house_value'].values
x_features = housing_data.drop(['median_house_value'], axis = 1)

from sklearn.cross_validation import train_test_split
from sklearn import model_selection

train_x, test_x, train_y, test_y = model_selection.train_test_split(x_features, y_target, test_size=0.2, random_state=4)
reg = linear_model.SGDRegressor(random_state=0)
cv = ShuffleSplit(n_splits = 10, test_size = 0.2, random_state = 0)


The error is below:

---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-22-8f8760b04f8c> in <module>()
----> 1 cv = ShuffleSplit(n_splits = 10, test_size = 0.2, random_state = 0)

TypeError: __init__() got an unexpected keyword argument 'n_splits'


I updated scikit-learn with 0.18 version.

Anaconda version: 4.5.8

Could you please advise on this issue?

Well, does ShuffleSplit accept an n_splits parameter?
– Lasse Vågsæther Karlsen
1 hour ago

ShuffleSplit

n_splits

Use n=10 instead of n_splits
– RafaelC
1 hour ago

n=10

n_splits

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