![The name of the picture]( "Creative")
JavaScript closure inside loops – simple practical example
var funcs = ;
for (var i = 0; i < 3; i++) // let's create 3 functions
funcs[i] = function() // and store them in funcs
console.log("My value: " + i); // each should log its value.
;
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
It outputs this:
My value: 3
My value: 3
My value: 3
Whereas I'd like it to output:
My value: 0
My value: 1
My value: 2
The same problem occurs when the delay in running the function is caused by using event listeners:
var buttons = document.getElementsByTagName("button");
for (var i = 0; i < buttons.length; i++) // let's create 3 functions
buttons[i].addEventListener("click", function() // as event listeners
console.log("My value: " + i); // each should log its value.
);
<button>0</button><br>
<button>1</button><br>
<button>2</button>
… or asynchronous code, e.g. using Promises:
// Some async wait function
const wait = (ms) => new Promise((resolve, reject) => setTimeout(resolve, ms));
for(var i = 0; i < 3; i++)
wait(i * 100).then(() => console.log(i)); // Log `i` as soon as each promise resolves.
What’s the solution to this basic problem?
funcs
37 Answers
37
Well, the problem is that the variable i, within each of your anonymous functions, is bound to the same variable outside of the function.
i
Classic solution: Closures
What you want to do is bind the variable within each function to a separate, unchanging value outside of the function:
var funcs = ;
function createfunc(i)
return function() console.log("My value: " + i); ;
for (var i = 0; i < 3; i++)
funcs[i] = createfunc(i);
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
Since there is no block scope in JavaScript - only function scope - by wrapping the function creation in a new function, you ensure that the value of "i" remains as you intended.
2015 Solution: forEach
With the relatively widespread availability of the Array.prototype.forEach function (in 2015), it's worth noting that in those situations involving iteration primarily over an array of values, .forEach() provides a clean, natural way to get a distinct closure for every iteration. That is, assuming you've got some sort of array containing values (DOM references, objects, whatever), and the problem arises of setting up callbacks specific to each element, you can do this:
Array.prototype.forEach
.forEach()
var someArray = [ /* whatever */ ];
// ...
someArray.forEach(function(arrayElement)
// ... code code code for this one element
someAsynchronousFunction(arrayElement, function()
arrayElement.doSomething();
);
);
The idea is that each invocation of the callback function used with the .forEach loop will be its own closure. The parameter passed in to that handler is the array element specific to that particular step of the iteration. If it's used in an asynchronous callback, it won't collide with any of the other callbacks established at other steps of the iteration.
.forEach
If you happen to be working in jQuery, the $.each() function gives you a similar capability.
$.each()
ES6 solution: let
let
ECMAScript 6 (ES6), the newest version of JavaScript, is now starting to be implemented in many evergreen browsers and backend systems. There are also transpilers like Babel that will convert ES6 to ES5 to allow usage of new features on older systems.
ES6 introduces new let and const keywords that are scoped differently than var-based variables. For example, in a loop with a let-based index, each iteration through the loop will have a new value of i where each value is scoped inside the loop, so your code would work as you expect. There are many resources, but I'd recommend 2ality's block-scoping post as a great source of information.
let
const
var
let
i
for (let i = 0; i < 3; i++)
funcs[i] = function()
console.log("My value: " + i);
;
Beware, though, that IE9-IE11 and Edge prior to Edge 14 support let but get the above wrong (they don't create a new i each time, so all the functions above would log 3 like they would if we used var). Edge 14 finally gets it right.
let
i
var
function createfunc(i) return function() console.log("My value: " + i); ;
i
Function.bind()
.bind()
.bind()
this
i
.bind()
Try:
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = (function(index)
return function()
console.log("My value: " + index);
;
(i));
for (var j = 0; j < 3; j++)
funcs[j]();
Edit (2014):
Personally I think @Aust's more recent answer about using .bind is the best way to do this kind of thing now. There's also lo-dash/underscore's _.partial when you don't need or want to mess with bind's thisArg.
.bind
_.partial
bind
thisArg
}(i));
Another way that hasn't been mentioned yet is the use of Function.prototype.bind
Function.prototype.bind
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = function(x)
console.log('My value: ' + x);
.bind(this, i);
for (var j = 0; j < 3; j++)
funcs[j]();
UPDATE
As pointed out by @squint and @mekdev, you get better performance by creating the function outside the loop first and then binding the results within the loop.
function log(x)
console.log('My value: ' + x);
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = log.bind(this, i);
for (var j = 0; j < 3; j++)
funcs[j]();
_.partial
.bind()
.bind()
.bind()
bind
Using an Immediately-Invoked Function Expression, the simplest and most readable way to enclose an index variable:
for (var i = 0; i < 3; i++)
(function(index)
console.log('iterator: ' + index);
//now you can also loop an ajax call here
//without losing track of the iterator value: $.ajax();
)(i);
This sends the iterator i into the anonymous function of which we define as index. This creates a closure, where the variable i gets saved for later use in any asynchronous functionality within the IIFE.
i
index
i
i
index
index
i
var funcs = ; for (var i = 0; i < 3; i++) funcs[i] = (function(index) return function() console.log('iterator: ' + index);; )(i); ; for (var j = 0; j < 3; j++) funcs[j]();
.forEach()
forEach()
var nums [4, 6, 7]; var funcs = ; nums.forEach(function (num, i) funcs[i] = function () console.log(num); ; );
Bit late to the party, but I was exploring this issue today and noticed that many of the answers don't completely address how Javascript treats scopes, which is essentially what this boils down to.
So as many others mentioned, the problem is that the inner function is referencing the same i variable. So why don't we just create a new local variable each iteration, and have the inner function reference that instead?
i
//overwrite console.log() so you can see the console output
console.log = function(msg) document.body.innerHTML += '<p>' + msg + '</p>';;
var funcs = ;
for (var i = 0; i < 3; i++)
var ilocal = i; //create a new local variable
funcs[i] = function()
console.log("My value: " + ilocal); //each should reference its own local variable
;
for (var j = 0; j < 3; j++)
funcs[j]();
Just like before, where each inner function outputted the last value assigned to i, now each inner function just outputs the last value assigned to ilocal. But shouldn't each iteration have it's own ilocal?
i
ilocal
ilocal
Turns out, that's the issue. Each iteration is sharing the same scope, so every iteration after the first is just overwriting ilocal. From MDN:
ilocal
Important: JavaScript does not have block scope. Variables introduced with a block are scoped to the containing function or script, and the effects of setting them persist beyond the block itself. In other words, block statements do not introduce a scope. Although "standalone" blocks are valid syntax, you do not want to use standalone blocks in JavaScript, because they don't do what you think they do, if you think they do anything like such blocks in C or Java.
Reiterated for emphasis:
We can see this by checking ilocal before we declare it in each iteration:
ilocal
//overwrite console.log() so you can see the console output
console.log = function(msg) document.body.innerHTML += '<p>' + msg + '</p>';;
var funcs = ;
for (var i = 0; i < 3; i++)
console.log(ilocal);
var ilocal = i;
This is exactly why this bug is so tricky. Even though you are redeclaring a variable, Javascript won't throw an error, and JSLint won't even throw a warning. This is also why the best way to solve this is to take advantage of closures, which is essentially the idea that in Javascript, inner functions have access to outer variables because inner scopes "enclose" outer scopes.
This also means that inner functions "hold onto" outer variables and keep them alive, even if the outer function returns. To utilize this, we create and call a wrapper function purely to make a new scope, declare ilocal in the new scope, and return an inner function that uses ilocal (more explanation below):
ilocal
ilocal
//overwrite console.log() so you can see the console output
console.log = function(msg) document.body.innerHTML += '<p>' + msg + '</p>';;
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = (function() //create a new scope using a wrapper function
var ilocal = i; //capture i into a local var
return function() //return the inner function
console.log("My value: " + ilocal);
;
)(); //remember to run the wrapper function
for (var j = 0; j < 3; j++)
funcs[j]();
Creating the inner function inside a wrapper function gives the inner function a private environment that only it can access, a "closure". Thus, every time we call the wrapper function we create a new inner function with it's own separate environment, ensuring that the ilocal variables don't collide and overwrite each other. A few minor optimizations gives the final answer that many other SO users gave:
ilocal
//overwrite console.log() so you can see the console output
console.log = function(msg) document.body.innerHTML += '<p>' + msg + '</p>';;
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = wrapper(i);
for (var j = 0; j < 3; j++)
funcs[j]();
//creates a separate environment for the inner function
function wrapper(ilocal)
return function() //return the inner function
console.log("My value: " + ilocal);
;
Update
With ES6 now mainstream, we can now use the new let keyword to create block-scoped variables:
let
//overwrite console.log() so you can see the console output
console.log = function(msg) document.body.innerHTML += '<p>' + msg + '</p>';;
var funcs = ;
for (let i = 0; i < 3; i++) // use "let" to declare "i"
funcs[i] = function()
console.log("My value: " + i); //each should reference its own local variable
;
for (var j = 0; j < 3; j++) // we can use "var" here without issue
funcs[j]();
Look how easy it is now! For more information see this answer, which my info is based off of.
let
const
let
i=0; while(i < 100) setTimeout(function() window.open("https://www.bbc.com","_self") , 3000); setTimeout(function() window.open("https://www.cnn.com","_self") , 3000); i++
i
With ES6 now widely supported, the best answer to this question has changed. ES6 provides the let and const keywords for this exact circumstance. Instead of messing around with closures, we can just use let to set a loop scope variable like this:
let
const
let
var funcs = ;
for (let i = 0; i < 3; i++)
funcs[i] = function()
console.log("My value: " + i);
;
val will then point to an object that is specific to that particular turn of the loop, and will return the correct value without the additional closure notation. This obviously significantly simplifies this problem.
val
const is similar to let with the additional restriction that the variable name can't be rebound to a new reference after initial assignment.
const
let
Browser support is now here for those targeting the latest versions of browsers. const/let are currently supported in the latest Firefox, Safari, Edge and Chrome. It also is supported in Node, and you can use it anywhere by taking advantage of build tools like Babel. You can see a working example here: http://jsfiddle.net/ben336/rbU4t/2/
const
let
Docs here:
Beware, though, that IE9-IE11 and Edge prior to Edge 14 support let but get the above wrong (they don't create a new i each time, so all the functions above would log 3 like they would if we used var). Edge 14 finally gets it right.
let
i
var
Another way of saying it is that the i in your function is bound at the time of executing the function, not the time of creating the function.
i
When you create the closure, i is a reference to the variable defined in the outside scope, not a copy of it as it was when you created the closure. It will be evaluated at the time of execution.
i
Most of the other answers provide ways to work around by creating another variable that won't change the value for you.
Just thought I'd add an explanation for clarity. For a solution, personally, I'd go with Harto's since it is the most self-explanatory way of doing it from the answers here. Any of the code posted will work, but I'd opt for a closure factory over having to write a pile of comments to explain why I'm declaring a new variable(Freddy and 1800's) or have weird embedded closure syntax(apphacker).
What you need to understand is the scope of the variables in javascript is based on the function. This is an important difference than say c# where you have block scope, and just copying the variable to one inside the for will work.
Wrapping it in a function that evaluates returning the function like apphacker's answer will do the trick, as the variable now has the function scope.
There is also a let keyword instead of var, that would allow using the block scope rule. In that case defining a variable inside the for would do the trick. That said, the let keyword isn't a practical solution because of compatibility.
var funcs = ;
for (var i = 0; i < 3; i++)
let index = i; //add this
funcs[i] = function()
console.log("My value: " + index); //change to the copy
;
for (var j = 0; j < 3; j++)
funcs[j]();
Here's another variation on the technique, similar to Bjorn's (apphacker), which lets you assign the variable value inside the function rather than passing it as a parameter, which might be clearer sometimes:
for (var i = 0; i < 3; i++)
funcs[i] = (function()
var index = i;
return function()
console.log("My value: " + index);
)();
Note that whatever technique you use, the index variable becomes a sort of static variable, bound to the returned copy of the inner function. I.e., changes to its value are preserved between calls. It can be very handy.
index
var
return
var
return
This describes the common mistake with using closures in JavaScript.
Consider:
function makeCounter()
var obj = counter: 0;
return
inc: function()obj.counter ++;,
get: function()return obj.counter;
;
counter1 = makeCounter();
counter2 = makeCounter();
counter1.inc();
alert(counter1.get()); // returns 1
alert(counter2.get()); // returns 0
For each time makeCounter is invoked, counter: 0 results in a new object being created. Also, a new copy of obj
is created as well to reference the new object. Thus, counter1 and counter2 are independent of each other.
makeCounter
counter: 0
obj
counter1
counter2
Using a closure in a loop is tricky.
Consider:
var counters = ;
function makeCounters(num)
for (var i = 0; i < num; i++)
var obj = counter: 0;
counters[i] =
inc: function()obj.counter++;,
get: function()return obj.counter;
;
makeCounters(2);
counters[0].inc();
alert(counters[0].get()); // returns 1
alert(counters[1].get()); // returns 1
Notice that counters[0] and counters[1] are not independent. In fact, they operate on the same obj!
counters[0]
counters[1]
obj
This is because there is only one copy of obj shared across all iterations of the loop, perhaps for performance reasons.
Even though counter: 0 creates a new object in each iteration, the same copy of obj will just get updated with a
reference to the newest object.
obj
counter: 0
obj
Solution is to use another helper function:
function makeHelper(obj)
return
inc: function()obj.counter++;,
get: function()return obj.counter;
;
function makeCounters(num)
for (var i = 0; i < num; i++)
var obj = counter: 0;
counters[i] = makeHelper(obj);
This works because local variables in the function scope directly, as well as function argument variables, are allocated
new copies upon entry.
For a detailed discussion, please see JavaScript closure pitfalls and usage
The most simple solution would be,
Instead of using:
var funcs = ;
for(var i =0; i<3; i++)
funcs[i] = function()
alert(i);
for(var j =0; j<3; j++)
funcs[j]();
which alerts "2", for 3 times. This is because anonymous functions created in for loop, shares same closure, and in that closure, the value of i is the same. Use this to prevent shared closure:
i
var funcs = ;
for(var new_i =0; new_i<3; new_i++)
(function(i)
funcs[i] = function()
alert(i);
)(new_i);
for(var j =0; j<3; j++)
funcs[j]();
The idea behind this is, encapsulating the entire body of the for loop with an IIFE (Immediately-Invoked Function Expression) and passing new_i as a parameter and capturing it as i. Since the anonymous function is executed immediately, the i value is different for each function defined inside the anonymous function.
new_i
i
i
This solution seems to fit any such problem since it will require minimal changes to the original code suffering from this issue. In fact, this is by design, it should not be an issue at all!
no array
no extra for loop
for (var i = 0; i < 3; i++)
createfunc(i)();
function createfunc(i)
return function()console.log("My value: " + i);;
http://jsfiddle.net/7P6EN/
The main issue with the code shown by the OP is that i is never read until the second loop. To demonstrate, imagine seeing an error inside of the code
i
funcs[i] = function() // and store them in funcs
throw new Error("test");
console.log("My value: " + i); // each should log its value.
;
The error actually does not occur until funcs[someIndex] is executed (). Using this same logic, it should be apparent that the value of i is also not collected until this point either. Once the original loop finishes, i++ brings i to the value of 3 which results in the condition i < 3 failing and the loop ending. At this point, i is 3 and so when funcs[someIndex]() is used, and i is evaluated, it is 3 - every time.
funcs[someIndex]
()
i
i++
i
3
i < 3
i
3
funcs[someIndex]()
i
To get past this, you must evaluate i as it is encountered. Note that this has already happened in the form of funcs[i] (where there are 3 unique indexes). There are several ways to capture this value. One is to pass it in as a parameter to a function which is shown in several ways already here.
i
funcs[i]
Another option is to construct a function object which will be able to close over the variable. That can be accomplished thusly
jsFiddle Demo
jsFiddle Demo
funcs[i] = new function()
var closedVariable = i;
return function()
console.log("My value: " + closedVariable);
;
;
Here's a simple solution that uses forEach (works back to IE9):
forEach
var funcs = ;
[0,1,2].forEach(function(i) // let's create 3 functions
funcs[i] = function() // and store them in funcs
console.log("My value: " + i); // each should log its value.
;
)
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
Prints:
My value: 0
My value: 1
My value: 2
JavaScript functions "close over" the scope they have access to upon declaration, and retain access to that scope even as variables in that scope change.
var funcs =
for (var i = 0; i < 3; i += 1)
funcs[i] = function ()
console.log(i)
for (var k = 0; k < 3; k += 1)
funcs[k]()
Each function in the array above closes over the global scope (global, simply because that happens to be the scope they're declared in).
Later those functions are invoked logging the most current value of i in the global scope. That's the magic, and frustration, of closure.
i
"JavaScript Functions close over the scope they are declared in, and retain access to that scope even as variable values inside of that scope change."
Using let instead of var solves this by creating a new scope each time the for loop runs, creating a separated scope for each function to close over. Various other techniques do the same thing with extra functions.
let
var
for
var funcs =
for (let i = 0; i < 3; i += 1)
funcs[i] = function ()
console.log(i)
for (var k = 0; k < 3; k += 1)
funcs[k]()
(let makes variables that are block scoped instead of function scoped. Blocks are denoted by curly braces, but in the case of the for loop the initialization variable, i in our case, is considered to be declared in the braces.)
let
i
i
for
i
funcs[j]
i
i
After reading through various solutions, I'd like to add that the reason those solutions work is to rely on the concept of scope chain. It's the way JavaScript resolve a variable during execution.
var
arguments
window
In the initial code:
funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = function inner() // function inner's scope contains nothing
console.log("My value: " + i);
;
console.log(window.i) // test value 'i', print 3
When funcs gets executed, the scope chain will be function inner -> global. Since the variable i cannot be found in function inner (neither declared using var nor passed as arguments), it continues to search, until the value of i is eventually found in the global scope which is window.i.
funcs
function inner -> global
i
function inner
var
i
window.i
By wrapping it in an outer function either explicitly define a helper function like harto did or use an anonymous function like Bjorn did:
funcs = ;
function outer(i) // function outer's scope contains 'i'
return function inner() // function inner, closure created
console.log("My value: " + i);
;
for (var i = 0; i < 3; i++)
funcs[i] = outer(i);
console.log(window.i) // print 3 still
When funcs gets executed, now the scope chain will be function inner -> function outer. This time i can be found in the outer function's scope which is executed 3 times in the for loop, each time has value i bound correctly. It won't use the value of window.i when inner executed.
funcs
function inner -> function outer
i
i
window.i
More detail can be found here
It includes the common mistake in creating closure in the loop as what we have here, as well as why we need closure and the performance consideration.
Array.prototype.forEach(function callback(el) )
forEach
el
With new features of ES6 block level scoping is managed:
var funcs = ;
for (let i = 0; i < 3; i++) // let's create 3 functions
funcs[i] = function() // and store them in funcs
console.log("My value: " + i); // each should log its value.
;
for (let j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
The code in OP's question is replaced with let instead of var.
let
var
const
const
let
I'm surprised no one yet has suggested using the forEach function to better avoid (re)using local variables. In fact, I'm not using for(var i ...) at all anymore for this reason.
forEach
for(var i ...)
[0,2,3].forEach(function(i) console.log('My value:', i); );
// My value: 0
// My value: 2
// My value: 3
// edited to use forEach instead of map.
forEach
.forEach()
First of all, understand what's wrong with this code:
var funcs = ;
for (var i = 0; i < 3; i++) // let's create 3 functions
funcs[i] = function() // and store them in funcs
console.log("My value: " + i); // each should log its value.
;
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
Here when the funcs array is being initialized, i is being incremented, the funcs array is initialized and the size of func array becomes 3, so i = 3,.
Now when the funcs[j]() is called, it is again using the variable i, which has already been incremented to 3.
funcs
i
funcs
func
i = 3,
funcs[j]()
i
Now to solve this, we have many options. Below are two of them:
We can initialize i with let or initialize a new variable index with let and make it equal to i. So when the call is being made, index will be used and its scope will end after initialization. And for calling, index will be initialized again:
i
let
index
let
i
index
index
var funcs = ;
for (var i = 0; i < 3; i++)
let index = i;
funcs[i] = function()
console.log("My value: " + index);
;
for (var j = 0; j < 3; j++)
funcs[j]();
Other Option can be to introduce a tempFunc which returns the actual function:
tempFunc
var funcs = ;
function tempFunc(i)
return function()
console.log("My value: " + i);
;
for (var i = 0; i < 3; i++)
funcs[i] = tempFunc(i);
for (var j = 0; j < 3; j++)
funcs[j]();
This question really shows the history of JavaScript! Now we can avoid block scoping with arrow functions and handle loops directly from DOM nodes using Object methods.
const funcs = [1, 2, 3].map(i => () => console.log(i));
funcs.map(fn => fn())
const buttons = document.getElementsByTagName("button");
Object
.keys(buttons)
.map(i => buttons[i].addEventListener('click', () => console.log(i)));
<button>0</button><br>
<button>1</button><br>
<button>2</button>
We will check , what actually happens when you declare var and let
one by one.
var
let
var
<script>
var funcs = ;
for (var i = 0; i < 3; i++)
funcs[i] = function ()
debugger;
console.log("My value: " + i);
;
console.log(funcs);
</script>
Now open your chrome console window by pressing F12 and refresh the page.
Expend every 3 functions inside the array.You will see an property called [[Scopes]].Expand that one. You will see one
array object called "Global",expand that one. You will find a property 'i' declared into the object which having value 3.
[[Scopes]]
"Global"
'i'
Conclusion:
'var'
i
window.i
console.log("My value: " + i)
Global
Now replace the 'var' with 'let'
'var'
'let'
<script>
var funcs = ;
for (let i = 0; i < 3; i++)
funcs[i] = function ()
debugger;
console.log("My value: " + i);
;
console.log(funcs);
</script>
Do the same thing, Go to the scopes . Now you will see two objects "Block" and "Global". Now expand Block object , you
will see 'i' is defined there , and the strange thing is that , for every functions , the value if i is different (0 , 1, 2).
"Block"
"Global"
Block
i
Conclusion:
When you declare variable using 'let' even outside the function but inside the loop , this variable will not be a Global
variable , it will become a Block level variable which is only available for the same function only.That is the reason , we
are getting value of i different for each function when we invoke the functions.
'let'
Block
i
For more detail about how closer works , please go through the awesome video tutorial https://youtu.be/71AtaJpJHw0
I prefer to use forEach function, which has its own closure with creating a pseudo range:
forEach
var funcs = ;
new Array(3).fill(0).forEach(function (_, i) // creating a range
funcs[i] = function()
// now i is safely incapsulated
console.log("My value: " + i);
;
);
for (var j = 0; j < 3; j++)
funcs[j](); // 0, 1, 2
That looks uglier than ranges in other languages, but IMHO less monstrous than other solutions.
The reason your original example did not work is that all the closures you created in the loop referenced the same frame. In effect, having 3 methods on one object with only a single i variable. They all printed out the same value.
i
You could use a declarative module for lists of data such as query-js(*). In these situations I personally find a declarative approach less surprising
var funcs = Query.range(0,3).each(function(i)
return function()
console.log("My value: " + i);
;
);
You could then use your second loop and get the expected result or you could do
funcs.iterate(function(f) f(); );
(*) I'm the author of query-js and therefor biased towards using it, so don't take my words as a recommendation for said library only for the declarative approach :)
Query.range(0,3)
And yet another solution: instead of creating another loop, just bind the this to the return function.
this
var funcs = ;
function createFunc(i)
return function()
console.log('My value: ' + i); //log value of i.
.call(this);
for (var i = 1; i <= 5; i++) //5 functions
funcs[i] = createFunc(i); // call createFunc() i=5 times
By binding this, solves the problem as well.
Many solutions seem correct but they don't mention it's called Currying which is a functional programming design pattern for situations like here. 3-10 times faster than bind depending on the browser.
Currying
var funcs = ;
for (var i = 0; i < 3; i++) // let's create 3 functions
funcs[i] = curryShowValue(i);
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
function curryShowValue(i)
return function showValue()
console.log("My value: " + i);
See the performance gain in different browsers.
Your code doesn't work, because what it does is:
Create variable `funcs` and assign it an empty array;
Loop from 0 up until it is less than 3 and assign it to variable `i`;
Push to variable `funcs` next function:
// Only push (save), but don't execute
**Write to console current value of variable `i`;**
// First loop has ended, i = 3;
Loop from 0 up until it is less than 3 and assign it to variable `j`;
Call `j`-th function from variable `funcs`:
**Write to console current value of variable `i`;**
// Ask yourself NOW! What is the value of i?
Now the question is, what is the value of variable i when the function is called? Because the first loop is created with the condition of i < 3, it stops immediately when the condition is false, so it is i = 3.
i
i < 3
i = 3
You need to understand that, in time when your functions are created, none of their code is executed, it is only saved for later. And so when they are called later, the interpreter executes them and asks: "What is the current value of i?"
i
So, your goal is to first save the value of i to function and only after that save the function to funcs. This could be done for example this way:
i
funcs
var funcs = ;
for (var i = 0; i < 3; i++) // let's create 3 functions
funcs[i] = function(x) // and store them in funcs
console.log("My value: " + x); // each should log its value.
.bind(null, i);
for (var j = 0; j < 3; j++)
funcs[j](); // and now let's run each one to see
This way, each function will have it's own variable x and we set this x to the value of i in each iteration.
x
x
i
This is only one of the multiple ways to solve this problem.
Use closure structure, this would reduce your extra for loop. You can do it in a single for loop:
var funcs = ;
for (var i = 0; i < 3; i++)
(funcs[i] = function()
console.log("My value: " + i);
)(i);
COUNTER BEING A PRIMITIVE
Let's define callback functions as follows:
// ****************************
// COUNTER BEING A PRIMITIVE
// ****************************
function test1()
for (var i=0; i<2; i++)
setTimeout(function()
console.log(i);
);
test1();
// 2
// 2
After timeout completes it will print 2 for both. This is because the callback function accesses the value based on the lexical scope, where it was function was defined.
To pass and preserve the value while callback was defined, we can create a closure, to preserve the value before the callback is invoked. This can be done as follows:
function test2()
function sendRequest(i)
setTimeout(function()
console.log(i);
);
for (var i = 0; i < 2; i++)
sendRequest(i);
test2();
// 1
// 2
Now what's special about this is "The primitives are passed by value and copied. Thus when the closure is defined, they keep the value from the previous loop."
COUNTER BEING AN OBJECT
Since closures have access to parent function variables via reference, this approach would differ from that for primitives.
// ****************************
// COUNTER BEING AN OBJECT
// ****************************
function test3()
var index = i: 0 ;
for (index.i=0; index.i<2; index.i++)
setTimeout(function()
console.log('test3: ' + index.i);
);
test3();
// 2
// 2
So, even if a closure is created for the variable being passed as an object, the value of the loop index will not be preserved. This is to show that the values of an object are not copied whereas they are accessed via reference.
function test4()
var index = i: 0 ;
function sendRequest(index, i)
setTimeout(function()
console.log('index: ' + index);
console.log('i: ' + i);
console.log(index[i]);
);
for (index.i=0; index.i<2; index.i++)
sendRequest(index, index.i);
test4();
// index: i: 2
// 0
// undefined
// index: i: 2
// 1
// undefined
This is a problem often encountered with asynchronous code, the variable i is mutable and at the time at which the function call is made the code using i will be executed and i will have mutated to its last value, thus meaning all functions created within the loop will create a closure and i will be equal to 3 (the upper bound + 1 of the for loop.
i
i
i
i
for
A workaround to this, is to create a function that will hold the value of i for each iteration and force a copy i (as it is a primitive, think of it as a snapshot if it helps you).
i
i
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Mixing
You sure you don't want
funcsto be an array, if you're using numeric indices? Just a heads up.– DanMan
Jul 26 '13 at 11:12