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How to create var name with multiple var using javascript?

I want to create create var name a_test_3_check from multiple var and text using javascript For this code , i want to alert test

a_test_3_check

test

I tried to do with this code but not work. how can i do ?

<script>
var a_test_3_check = "test";

var x = "test";
var y = "check";

var z = 'a_'+x+ '_3_' +y;
alert(z);
</script>


And when i test code i alway alert a_test_3_check, how can i do ?

a_test_3_check

Thank you for every question.

Just getting my comment in before someone posts an answer using eval(): if you run into a situation where you have to dynamically construct and evaluate variable names, there is most likely something wrong with your design. Explain what you're trying to achieve, and we can help you think of alternatives.
– Robby Cornelissen
30 mins ago

eval()

@RobbyCornelissen To expand on this there is never a reason why you would need to do this. The name of a variable should have not have an impact on the functionality of your code.
– Spencer Wieczorek
24 mins ago

@SpencerWieczorek We are in complete agreement. Yet, there are already two eval() answers and they are even getting upvoted.
– Robby Cornelissen
23 mins ago

eval()

Don't do that. You should not generate variable names dynamically. At the most, you should create a JavaScript object and then get the value, based on its key, which is perfectly fine. Read working with objects.
– 31piy
23 mins ago

2 Answers
2

You can use eval(), If the argument to this function represents an expression, eval() evaluates the expression. If the argument represents one or more JavaScript statements, eval() evaluates the statements

eval()

eval()

eval()

var z = eval('a_'+x+ '_3_' +y);

var z = eval('a_'+x+ '_3_' +y);

If you try with eval() then you will get what you want.

eval()

var a_test_3_check = "test";

var x = "test";
var y = "check";

var z = 'a_'+x+ '_3_' +y;
alert(eval(z));


BUT, YOU SHOULD NOT USE eval() coz it not the proper way to get variable of variable, try using object structure though.

eval()

var obj =
x: "test",
y: "check",
a_test_3_check: "test"
;

var z = 'a_' + obj.x + '_3_' + obj.y;
console.log(obj[z]);

down voter, see my edit.. I wast writing the code, in the meantime you just down voted twice.Didn't wait for my full answer :(
– Being Sunny
17 mins ago

1) Nobody can downvote twice 2) If you want people to wait for your complete answer before they vote, don't post before you have a complete answer.
– Robby Cornelissen
12 mins ago

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